平稳正态序列谱函数估计的收敛速度

CONVERGENCE RATES OF ESTIMATE OF SPECTRAL FUNCTION FOR STATIONARY GAUSSIAN SERIES

  • 摘要: 本文主要讨论实平稳正态序列谱函数估计的a.s.(一致)收敛速度。首先,对实平稳正态序列的观察值的二次型建立指数不等式和概率1的界;在此基础上,得到了协方差函数和谱函数估计的收敛速度及一致收敛速度。

     

    Abstract: Suppose X=xn), n=0, ±1, … is a real strictly stationary process, Exn)=0, Exnxm)=Bn-m).Let fλ) and F \ddot( )=\int_0^\lambda f(u) d u be the spectral density and spectral function of X respectively. One way to estimate Bk) and Fλ) from N consecutive observations xj),j= 1, 2, …,N is by means of \begingathered \hatB_N(k)= \begincases\frac1N \sum_n=1^N-k x\left(n^\prime x(n+k)\right. & 0 \leqslant k \leqslant N-1 \\ 0 & k \geqslant N\endcases \\ \hatF_N(\lambda)=\int_0^\lambda \frac12 \pi N \sum_k=1^X x(k) e^-i k u y^2 d u \endgathered and respectively. This paper is mainly concerned with the a. s. convergence rates of |\hatF_N(\lambda)-F(\lambda)| and \sup _0<\lambda x\left|\hatF_N(\lambda)-F(\lambda)\right| for a real stationary Gaussian process. First, we establish the a. s. convergence rates of the quadratic forms of the observations. Then we obtain the convergence rates of estimates of the covariances and spectral function. The main results are as follows. Lemma 1. Let X= xn) be a real stationary Gaussian process with zero mean and BN= (Bn-m)) the N×N covariance matrix of X. YN= X’NANXN-EX’NANXN where X’N=(x(1), …, xN)),AN is a N×N real symmetric matrix. If λμ is the maximum of the absolute value of the eigenvalues of BN1/2ANBN1/2, then for any fixed δ>0 and 0≤αδ/2(1+δλμ-1, we have \begingatheredE\lefte^\alpha Y_N\right \leqslant \exp \left\\frac1+\delta2 \alpha^2 \operatornameVar\left(Y_N\right)\right\ \\ \text and \quad E\lefte^\alpha \mid Y_X i\right \leqslant 2 \exp \left\\frac1+\delta2 \alpha^2 \operatornameVar\left(Y_N\right)\right\ .\endgathered. Theorem 1. Let X=\x(n)\ be a real stationary Gaussian process with zero mean, and f^2 \log ^+ f \in L0, \pi. Y_N=X_N^\prime A_N X_N-E X_N^\prime \cdot A_N X_N where X_N^\prime=(x(1), \cdots, x(N)), A_N is a N \times N real symmetric matrix. If \left\|A_*\right\| \triangle \sup _1 \mathrmI_2=1\left|Y^\prime A_N Y\right| \leqslant c \quad N \geqslant 1 and \lim _N \rightarrow \infty \frac1N \operatornameVar\left(Y_N\right)=a^2>0 'I'hen \varlimsup_N \rightarrow \infty \frac1\sqrt2 \overlineN \log N\left|Y_N\right| \leqslant a \quad \text a.s. Corollary 1. Let X=\x(n)\ satisfy the conditions of Theorem 1. Then (1) \forall k \geqslant 0 \left.\varlimsup_N \rightarrow \infty \sqrt\fracN2 \log N \hatB_N(k)-B(k) \right\rvert\, \leqslant d_k \quad \text a.s. where d_k^2=4 \pi \int_-\pi^\pi \cos ^2 k u f^2(u) d u (2) \forall \lambda \in0, \pi \varlimsup_N \rightarrow \infty \sqrt\fracN2 \log N\left|\hatF_N(\lambda)-F(\lambda)\right| \leqslant c_\lambda \quad \text a.s. where c_\lambda^2=2 \pi \int_0^\lambda f^2(u) d u Theorem 2. Let X=\x(n)\ satisfy the conditions of Theorem 1. Then for \begingathered P(N)=O(\sqrtN \log N) \\ \varlimsup_N \rightarrow \infty \sqrt\fracN2 \log N \sup _0< k< P(N)\left|\hatB_N(k)-B(k)\right| \leqslant \sqrt\frac32 d_0 \quad \text a.s. \\ d_0^2=4 \pi \int_-x^\pi f^2(u) d u . \endgathered where Moreover, if f \in \operatornameLip-\frac12 in 0, \pi, then \varlimsup_N \rightarrow \infty \sqrt\fracN2 \log N \sup _0< k< \infty\left|\hatB_N(k)-B(k)\right| \leqslant \sqrt2 d_0 \quad \text a.s. Theorem 3. Let X=\x(n)\ satisfy the conditions of Theorem 1. Then \varlimsup_N \rightarrow \infty \sqrt\fracN2 \log N \sup _0< \lambda< x\left|\hatF_N(\lambda)-F(\lambda)\right| \leqslant(\sqrt2+2) c_x \quad \text a.s. where c_\pi^2=2 \pi \int_0^\pi f^2(u) d u . Finally, using a result of 5, we obtain the convergence rates of estimate of spectral function for a real linear process. Proposition. Let X=\x(n)\ be a real linear process, x(n)=\sum_j=0^\infty \alpha(j) \varepsilon(n-j) \quad \sum_j=0^\infty|\alpha(j)|< \infty \quad \alpha(0)=1 where \\varepsilon(n)\ is a strictly stationary martingale difference and E\left(\varepsilon^2(n) \mid \mathscrF_n-1\right)=\sigma^2, \quad E \varepsilon^4(n)< \infty ; \mathscrF_n \triangleq \sigma\\varepsilon(m) ; m \leqslant n\ . If Then \begingathered \lim _N \rightarrow \infty \sqrtN \sum_k=N^\infty|\alpha(k)|=0 \\ \sup _0<\lambda<=\left|\hatF_N(\lambda)-F(\lambda)\right|=O\left(N^-\frac12(\log N)^\frac32\right) \quad \text as \endgathered

     

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